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POWER ELECTRONICS / INTERACTIVE LABUniversity of Vigo

Before studying rectifiers

Three-phase electrical system review

Connect the sine waves, rotating vectors, and voltage measurements. Discover where 120°, 30°, and √3 come from—and why the order of the terminals matters.

Balanced sinusoidal source · U–V–W sequence

Learning view

A view selects a representative measurement; it does not change the source amplitude or frequency, the cursor angle θ, or the fixed initial phases.

Cursor angle and initial phase: different roles

One time coordinate for all voltages

θ=ωt

θ is the electrical angle elapsed since t = 0. Moving the cursor selects another instant on the same waveforms.

An initial phase for each voltage

φU=0°
φV=−120°
φW=120°

The constants φU, φV, and φW are the sine phases at t = 0. They do not change when the cursor moves.

Instantaneous phase: add the two angles

vV=Vm⁢sin⁡(θ+φV)

The sine argument of vV is θ + φV. For vU it equals θ because φU = 0; that does not make every voltage's phase equal to the cursor angle.

These initial phases use the chosen sine convention and time origin. A different time origin would change their values, not their differences; moving the cursor does not change that origin. Arguments written with π use radians; readouts and examples marked ° use degrees.

Example: V when the cursor is at 90°

For a nonzero amplitude, at θ = 90°, φV remains −120°. The instantaneous phase is 90° − 120° = −30° and vV = −Vm/2. The 90° cursor position is not the initial phase of V.

Phase voltages · Fundamentals

Three phases, one frequency

The three voltages are measured relative to the same neutral N. They have the same peak Vm and frequency f, and are separated by 120° (2π/3 rad). The fixed initial phases are φU = 0, φV = −2π/3, and φW = +2π/3; θ is the common time angle.

vU=Vm⁢sin⁡(θ)
vV=Vm⁢sin⁡(θ−2π3)
vW=Vm⁢sin⁡(θ+2π3)
What to notice now

Track the positive maxima: U, then V, then W. The 120° spacing is between matching points of different phases—not between any two neighboring zero crossings.

Why does this happen?
At every instant, vU + vV + vW = 0. The vectors form a balanced set; their vertical projections also sum to zero. This does not mean that the three voltages are individually zero.
vU+vV+vW=0

The equivalent expression vW = Vm sin(θ − 4π/3) is identical to Vm sin(θ + 2π/3): the arguments differ by one complete turn, 2π rad. These are equivalent ways to write the fixed initial phase of W, not different cursor positions.

Shared source and cursor

V
Hz
°

Move θ to choose another instant. The time origin and all initial phases stay fixed; this is not an initial-phase adjustment.

The animation advances 30° per real second for observation. It is not a real-time reproduction of the electrical frequency. Manual angle changes pause it. The animation loops the two-period viewing window; initial phases stay fixed.

Source examples

Initial didactic values: 325 V phase peak and 50 Hz. These are examples for practice, not mandatory ratings of a three-phase system.

Waveforms at the same instant

Click or tap the plot to move the cursor. The slider and number field provide the same operation by keyboard. On narrow screens, scroll only the plot sideways.

Both phase and line voltages share one vertical scale, which follows the chosen phase peak. Read the axis values when changing the amplitude. The horizontal window always spans two periods; changing frequency changes the time labels, not the angular spacing.

Angles of the selected voltage:

Initial phase · fixed
Instantaneous phase · at the cursor

Phase RMS · Vph,rms
Vm/√2
Line RMS · VLL,rms
√3Vm/√2
Line peak · VLL,peak
√3Vm
Line / phase peak ratio
√3

RMS values are calculated over a full period of the sinusoidal source. They are not the current cursor values.

Period Te
Time for Δθ = 120°
Time for Δθ = 30°
Voltages, fixed initial phases, and phases at the cursor
k identifies each phase voltage or ordered line-voltage pair. φk is its initial sine phase at t = 0; θ + φk is its instantaneous phase at the cursor. Move the cursor: the first stays fixed, the second changes. No wrapping to one turn is applied. The numerical phases describe nonzero-amplitude voltages, not a cosine/RMS phasor convention.
QuantityInstantaneous (V)Peak (V)Initial phase φk (°)At cursor θ + φk (°)

CSV: UTF-8, comma separator, decimal point. 1,441 uniform samples from 0° to 720° inclusive, every 0.5°. Time is in seconds, voltages in volts. The final endpoint repeats the start of the periodic signal; omit it when averaging. Lines beginning with # contain provenance and settings; the data header follows them.

The plot and numerical table share one voltage unit, selected from the source amplitude. Standalone readings may use a different, explicitly shown SI prefix. Numerical inputs remain in the stated units; CSV voltages always remain in volts.

Columns: theta_deg, t_s, U_R_V, U_S_V, U_T_V, U_RS_V, U_ST_V, U_TR_V, U_RT_V, U_TS_V, U_SR_V, U_span_V, U_probe_V. N is always 0 V. U_probe_V uses the selected probe terminals; U_span_V is the optional mathematical envelope, not a simulated rectifier output. For compatibility, the existing column names retain their original notation: R→U, S→V, T→W. Thus U_R_V, U_S_V, and U_T_V record vU, vV, and vW; paired subscripts follow the same mapping. U_span_V and U_probe_V record vspan and the selected instantaneous voltage. Display-name metadata records this mapping; numerical values, polarities, and units are unchanged.

theta_deg is the sampled time angle ωt, not a voltage's initial phase; cursor_deg records the current cursor position in the metadata. The fixed initial phases and the extra on-screen angle column are not new CSV columns. Voltage samples keep exactly the documented convention.

Model consistency checks

The implementation checks the instantaneous phase sum, the loop identity vUV + vVW + vWU = 0, and the opposite-polarity identities. Tiny residuals can come from floating-point arithmetic. These checks do not validate a different physical model.

Peak vectors at the cursor

Vertical projection = instantaneous voltage; vector length = peak voltage. Its current direction is θ + its initial phase, not the initial phase alone. This uses the sine/vertical-projection convention.

The dashed construction starts at the positive-terminal vector tip and adds the negative of the other vector. The resultant starts at the origin. N is the zero vector.

The arc measures a fixed phase difference, not θ. It runs from U to W (120°) in the phase view, or from the first-terminal phase to the selected line voltage (±30°) in the next two views. Both vectors rotate together; their separation stays fixed.

Virtual voltmeter

Ideal, non-loading measurement of a potential difference. This is a reference-polarity diagram, not a simulated load circuit. N is the common zero-potential reference.

Keep the conventions straight

Notation and physical meaning

In this lesson, vU, vV, and vW denote instantaneous phase-to-neutral voltages. Vm is their common peak; an “rms” subscript explicitly identifies an RMS value. U, V, W, and N are upright terminal names, not variable indices. The rotating vectors use peak values. The positive phase sequence is U–V–W, corresponding to the original R–S–T names in the source and unchanged technical data keys. The sine function is written sin in all three languages.

The chosen origin is t = 0 at the upward zero crossing of vU, so φU = 0. The cursor is θ = ωt; it is not an adjustable initial phase. Initial phases are defined relative to this same origin and use the sine convention. Te = 1/f; the phase named W is not the period. Changing the origin would be a different operation, which this control does not perform.

θ=ωt,ω=2πf
Peak, instantaneous, and RMS are different

Teaching addition derived from the sinusoidal model. “ph” means phase-to-neutral and “LL” means line-to-line. For a sine wave, its RMS value is its peak divided by √2. Compare RMS with RMS, or peak with peak—not one of each.

Vph,rms=Vm2
VLL,rms=3Vm2
VLL,rms=3Vph,rms
VLL,peak=3Vm

Example: a 230 V phase RMS value gives about 398.372 V line RMS, 325.269 V phase peak, and 563.383 V line peak. “230/400 V” would be a rounded nominal description, not an exact equality used by this model.

Investigate before revealing the explanation

Each investigation has one question to test. Load its starting point, write a prediction, make the proposed change, and compare your observation with your explanation. Opening a solution does not overwrite your notes.

01120° is an angle, not a fixed time
Predict

Start at θ = 90°, f = 50 Hz. Which phase reaches its positive maximum next? Predict how the time to that maximum changes if the frequency is doubled.

Inspect the laboratory

The test change sets f to 100 Hz, keeping θ = 90°. Compare the 120° time interval, then move the cursor to the next positive phase maximum. The waveform window always spans two periods. As you move the cursor, compare the two angle columns in the table: initial phases stay fixed; instantaneous phases advance.

Check your explanation

V peaks next, at 210°. The angular interval stays at 120°, but Δt = 1/(3f) falls from 6.667 ms to 3.333 ms. Doubling the rate of rotation halves the time for the same angular displacement. Neither moving the cursor nor this frequency change alters φU, φV, or φW. At the same θ, all instantaneous sine arguments are unchanged too.

02Does the line peak occur at the phase peak?
Predict

Use Vm = 100 V and the UV measurement. Start at 90°, where U is at its positive peak. Predict vUV there and whether it is already at its own maximum.

Inspect the laboratory

Apply the test change to move to 60°. Compare both phase potentials and their difference at the two angles.

Check your explanation

At 90°, the potentials are 100 V and −50 V, so vUV = 150 V. At 60°, they are approximately 86.603 V and −86.603 V, giving the line peak 173.205 V. The largest difference is reached before the U peak; the phase voltages cannot simultaneously be +100 V and −100 V. Here φUV stays at +30°: the peak occurs at θ = 60° because θ + φUV = 90°.

03Reverse the probes, not the source sequence
Predict

Start with Vm = 100 V, θ = 0°, and the UV measurement. Predict the signed reading after exchanging the probes. Is the phase change 30°, 120°, or 180°?

Inspect the laboratory

The test change selects VU and displays the reversed-polarity line-voltage set. Keep the angle fixed, then examine other cursor positions.

Check your explanation

vUV is approximately +86.603 V and vVU is −86.603 V. Every sample changes sign; the peak and RMS are unchanged. This is a 180° shift of the same pair voltage. The 30° statement compares a line voltage with a phase voltage, so it is a different comparison. The cursor θ did not move. The initial phases of UV and VU differ by 180° modulo 360°.

04Follow all six positive peaks
Predict

Use a 1 V phase peak. Starting at 0°, record the line voltage with the positive peak at each successive 60° position. Predict when the pattern will repeat.

Inspect the laboratory

The test change moves from 0° to 60°. Continue with two +30° steps at a time. Compare the six line peaks with the three phase peaks.

Check your explanation

The order is WV, UV, UW, VW, VU, WU, then WV again at 360°. The line peaks are √3 V, whereas the phase peaks are 1 V. The original three direct line voltages are 120° apart; including their opposite polarities interleaves three more positive peaks.

05At a boundary, two answers can be correct
Predict

Optional extension. Start at 0° with Vm = 100 V and the maximum–minimum envelope visible. Predict which phases will be highest and lowest at 30°. Will one line voltage uniquely define the maximum?

Inspect the laboratory

Apply the test change to 30°. Then inspect 29° and 31° with the numerical angle field. Record the highest/lowest phases and the envelope value.

Check your explanation

At 30°, U and W both equal +50 V, while V equals −100 V. Therefore vUV = vWV = 150 V, the lower limit of the envelope. Just before the boundary, WV maximizes the difference; just after it, UV does. The voltages remain continuous. A voltage tie alone does not calculate a real diode commutation.

Check what you can explain

One correct answer per question. Submit your own answer before revealing a solution. First attempts, retries, and solutions viewed before answering are recorded separately. This is self-assessment, not a secure examination. The questions use their own stated conditions, independently of the current controls. Assume a nonzero source amplitude unless a question states otherwise.

The handout includes all four teaching views, investigations, your notes, and quiz solutions. It uses the current source settings and a light theme. Printing solutions does not record a quiz attempt or change your saved history.

Model, limits, and teaching reference

This laboratory calculates the steady periodic voltages of an ideal balanced three-phase sinusoidal source with fixed U–V–W sequence, equal phase peaks, a common frequency, and an ideal neutral reference. Line voltages are calculated by instantaneous subtraction. The source amplitude and frequency are prescribed, not solved from a generator or a network.

Not modeled: unbalance, harmonics, negative-sequence sources, source impedance, loads, phase or neutral currents, power, star/delta load connections, semiconductor states, or commutation transients. The √3 and ±30° relations shown here apply to the stated balanced sinusoidal source and the stated voltage ordering. They must not be applied indiscriminately to other systems. Numerical input limits: phase peak 0 V or 10⁻⁹–600 V; frequency 1–100 Hz; cursor 0–720°. Values smaller than the supported nonzero voltage range are rejected, not rounded silently to zero.

Teaching reference: Recordatorio Red Trifásica. This lesson retains its U–V–W sine convention, terminal ordering, and phase/line relationships. The interactive diagrams are redrawings. No accompanying presentation is needed to use the lesson.

ConceptRelationships covered
Phase voltagesThree 120°-spaced phase voltages, time traces, rotating vectors, and phase equations.
Line voltagesDirect line voltages, √3 peak factor, and 30° lead.
Reverse polaritiesReversed-polarity line voltages vUW, vWV, and vVU; their 30° lag relative to vU, vW, and vV, respectively.
Six line voltagesTwo-period phase overlay and the complete six-line-voltage overlay.

Explicit teaching additions: the virtual meter, derivations and convention notes, RMS conversions, numerical examples, linked cursor, optional maximum–minimum envelope and tie handling, investigations, and self-assessment. These are derived teaching aids, not additional claims attributed to the teaching reference.

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